What power would the solar cell produce?- Mastering Physics?

A large solar panel on a spacecraft in Earth orbit produces 2.0 of power when the panel is turned toward the sun.
What power would the solar cell produce if the spacecraft were in orbit around Saturn, 9.5 times as far from the sun?

So far, I’ve got:
Power of panel (pop) @ earth= Intensity earth(Iearth)* Area of panel
Pop @ saturn= Isatun* area of panel
then: PoP@earth/pop@saturn= R_s^2/R_e^2; where R_s and R_e is the distance of the sun to saturn and distance of the sun to earth. Thanks!

Comments

2 Responses to “What power would the solar cell produce?- Mastering Physics?”
  1. YahooUser says:

    Check!

  2. Bob D says:

    Output power would fall off with the square of the distance:

    P = [(S / (4 pi d^2))]

    P = Final Power in Watts
    S = Initial Power in Watts
    d = Distance

    Thus, r = d/2 = P
    2r = 1/4 P
    3r = 1/9 P

    ——————–
    2 Watts / (4 pi 9.5^2) = 1.76 E -3 or 1.76 miliWatts (0.00176 Watts)

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